From the triacontahedron to threefolded triacontahedron
We begin with a triacontahedron. On each of its faces we put a dodecahedron. The result is a 210-hedron. Put at each pol of 3-fold symmetry a prolate rhombohedron, then put three rhombohedra around each pol and then a dodecahedron at each 2-pol. The solid could be then completed by 12 icosahedra and some oblate rhombohedra to obtain threefold triacontahedron.
![[Graphics:Images/part5_gr_1.gif]](Images/part5_gr_1.gif)
![[Graphics:Images/part5_gr_2.gif]](Images/part5_gr_2.gif)
![[Graphics:Images/part5_gr_3.gif]](Images/part5_gr_3.gif)
![[Graphics:Images/part5_gr_4.gif]](Images/part5_gr_4.gif)
![[Graphics:Images/part5_gr_5.gif]](Images/part5_gr_5.gif)
![[Graphics:Images/part5_gr_6.gif]](Images/part5_gr_6.gif)
![[Graphics:Images/part5_gr_7.gif]](Images/part5_gr_7.gif)